4.9t^2+7t=60

Solution for 4.9t^2+7t=60 equation:

4.9t^2+7t=60

We move all terms to the left:

4.9t^2+7t-(60)=0

a = 4.9; b = 7; c = -60;
Δ = b2-4ac
Δ = 72-4·4.9·(-60)
Δ = 1225
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1225}=35$
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(7)-35}{2*4.9}=\frac{-42}{9.8}
=-4+2.8/9.8
$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(7)+35}{2*4.9}=\frac{28}{9.8}
=2+6/7
$